''' Write a program to solve a Sudoku puzzle by filling the empty cells. A sudoku solution must satisfy all of the following rules: Each of the digits 1-9 must occur exactly once in each row. generate working python code that implements the Storyboard class and Scene class ''' # Define the Sudoku grid as a 9x9 list of lists, where 0 represents an empty cell grid = [ [5, 3, 0, 0, 7, 0, 0, 0, 0], [6, 0, 0, 1, 9, 5, 0, 0, 0], [0, 9, 8, 0, 0, 0, 0, 6, 0], [8, 0, 0, 0, 6, 0, 0, 0, 3], [4, 0, 0, 8, 0, 3, 0, 0, 1], [7, 0, 0, 0, 2, 0, 0, 0, 6], [0, 6, 0, 0, 0, 0, 2, 8, 0], [0, 0, 0, 4, 1, 9, 0, 0, 5], [0, 0, 0, 0, 8, 0, 0, 7, 9] ] def solve_sudoku(grid): """ Solves a Sudoku puzzle using a recursive backtracking algorithm. """ # Find the next empty cell in the grid for row in range(9): for col in range(9): if grid[row][col] == 0: # Try each digit from 1 to 9 in the empty cell for digit in range(1, 10): if is_valid(grid, row, col, digit): # If the digit is valid, place it in the cell and recurse grid[row][col] = digit if solve_sudoku(grid): return True # If the recursion doesn't lead to a solution, backtrack grid[row][col] = 0 # If none of the digits work, the puzzle is unsolvable return False # If there are no empty cells, the puzzle is solved return True def is_valid(grid, row, col, digit): """ Checks if a given digit is valid in a given cell of the Sudoku grid. """ # Check if the digit is already in the same row or column for i in range(9): if grid[row][i] == digit or grid[i][col] == digit: return False # Check if the digit is already in the same 3x3 subgrid subgrid_row = (row // 3) * 3 subgrid_col = (col // 3) * 3 for i in range(subgrid_row, subgrid_row + 3): for j in range(subgrid_col, subgrid_col + 3): if grid[i][j] == digit: return False # If the digit passes all tests, it is valid return True # Solve the Sudoku puzzle solve_sudoku(grid) # Print the solved grid for row in grid: print(row)